Can you solve Martin Gardner's "coin of the realm" puzzle?

I can get it down to fifteen or so, you just need some coins to be negative values.

-1,-2,-3,-4,-5-,6-7-8- 9
And 10, 20, 30, 70 and 90

I think (?) That works.
But you have to allow negatives on your coinage.

You mean change?

As in, some coins have a negative value that subtracts from the value of another, so to get 61 you give a 70 coin and a -9 coin

Interestingly, Canada has some very specific limits on how much coin people are obligated to accept as payment. The limit for pennies is a mere 25 cents.

Really? I’d’ve thought it’d be 50 cents, since that’s how many pennies fit into a standard roll.

Yeah, that would make sense. I had to check to see if the law was passed before canada deprecated the penny - it looks like it was

ETA:
although if you were paying in nicely wrapped coin bundles, most people would probably be happy to accept all the pennies to feel like giving. I suspect this law is targeted specifically at griefers

20p for coppers (1p and 2p) in the UK. I can’t remember the limit for silver.

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The rest of them make sense: you can pay with a roll of nickels, dimes, quarters, or loonies (not toonies, but who’s going to pay more than $40 in coins?), but people are not obligated to accept a roll of pennies.

Huh.

Another reason to be glad we’re rid of the things.

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in Germany it’s 50 coins per transaction (but shops can set lower limits in the terms & conditions)

How would you get 41?

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