Hmmm, a quick guess here, a 100% effective strategy doesn’t seem to exist. If you eliminate one target, for certain, then the remaining one will target you 100% of the time, leaving you with either a 90% or 70% chance of losing before the round is over. So I would think you would take the 60%, least dangerous wand, and target the person with the 90% wand. The best possible outcome for you would be to take your turn and leave both your opponents unscathed. Because you are the least dangerous, your opponents best move would be to attack each other and take their chances with your next turn. So you either succeed with your first turn and take your 30% chance, or you fail and don’t get targeted at all and get an additional shot at your remaining opponent. I’m doing this without really doing any math, so I’m just assuming that the odds of all 3 wizards failing are considerably less than the 70% chance of your loss that the 100% wand would give you. I put my odds of being correct about this at about 25% watches the video
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