The way that the linear ratio 1⁄6 gets involved in the example is:
After 0.56 seconds on the moon, the object only falls 5⁄6 of a foot.
See? There is the factor of 1⁄6.
But the object does NOT take another 2.8 seconds to hit the ground.
It’s not starting from rest and falling the first ten inches six times.
d = 1⁄2 a t 2
t 2 = 2d ⁄a
t = √( 2d ⁄a )
The astronauts and their equipment are not supposed to be changing size, so we can ignore d. What is being simulated is a change in acceleration, a. In order to simulate that change in acceleration, the TIME dimension, t, the DURATION OF THE VIDEO, must be adjusted by the square root of the reciprocal of the change in acceleration.
