Odd Stuff (Part 1)

Thanks. I’ve not heard of the guy, but I do know that the old chair of my department, who was a Soviet historian, who also tore about a book about Stalin that this guy did not like as well. I think it’s a bit of a stretch to say that Stalin was and should be absolved of all crimes, and any accusations of wrong-doing on his part are lies made up by capitalists or his internal enemies. But it’s entirely unsurprising that there is a good deal of slanted work on Stalin, too, going both ways, really. I think this just shows how much of our work is driven by our own internal biases, and we have to acknowledge and account for it, rather than pretend that we don’t have them.

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So apparently as a transport policy wonk I’m a “New Left Urbanist”.

I’m cool with that, although to be honest I really want a better class of acronym than “NLU”.

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source%20(29)

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Porn Hub, Soooooo Dirty

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Well, they have reach, worldwide.

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Highly underrated

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The Tell-Tale Heart! Boffins build an AI that can tell your sex using just your heartbeat

LOOK THERE’S A PATTERN IN THE PRIME NUMBERS

the pattern is they’re never multiples of 2 or 3

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Reach around the world.

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b39

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Worldwide reach around.

Sorry, a bit of a stretch.

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“Reach out and touch someone.”

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Analytics of Doom*

*This headline was overly dramatized for your enjoyment.

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Bycatch:

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e996aa377567c7cff6722ea761efce47

(They are going to be ok.)

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Twitter thinks that vagina is a ■■■■■ word.

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Oops, I have Javascript disabled on new tabs by default

Now I know “reading math” is one of the things that requires Javascript

As for why Discourse doesn’t render quoted material like

We know for every positive integer $n$ , $ \sum_{k=1}^n k^2=\dfrac{n(n+1)(2n+1)}6$ . If $p>3$ is a prime then $\dfrac{p-1}2$ is a positive integer , so $$ \sum_{k=1}^{\dfrac{p-1}2} k^2=\dfrac{\dfrac{p-1}2\bigg(\dfrac{p-1}2+1\bigg)\Bigg(2\bigg(\dfrac{p-1}2\bigg)+1\Bigg)}6=\dfrac {(p-1)(p+1)p}{24}=\dfrac {p(p^2-1)}{24}$$ ,

so $\dfrac {p(p^2-1)}{24}$ is a sum of some positive integers , and hence an integer i.e. $24$ divides $p(p^2-1)$ , but

also $24=3 ×2^3$ and since $p>3$ is a prime , so $ g.c.d (p,24)=1$ , hence $24$ divides $p^2-1$

who knows

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