It could use a better explanation (show your workings!). I get slightly different values (maybe rounding errors though).
The time taken to fall is found by solving: s = ut + at^2
s(height) = 35.4; u(initial vertical velocity) = 40.3 sin45; a(gravity) = -9.8 m/s^2
Solve this to get t = 6.9 seconds of flight time
Horizontal velocity is a constant 40.3 cos45 = 28.5 m/s, if we ignore air resistance (it's equal to the initial vertical velocity in this case).
Distance travelled is 6.9*28.5 = 197 m
This is important since it means you may be lucky enough to miss the road and land on the path, saving you from being arrested for speeding in an unlicensed vehicle, since your terminal velocity (this is a pun) is 39 m/s vertically and 28.5 m/s horizontally, or 48 m/s in your direction of travel.
This is the first time I've solved a quadratic equation in many years. Good to see my education wasn't entirely worthless.
Edit: I think I've been sniped: http://xkcd.com/356/